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Re: [RiminiLUG-General] java Exception



Filippo Giunchedi ha scritto:
On Tue, Jan 19, 2010 at 03:41:19PM +0100, Simeone wrote:
Non riesco ad intercettare l'errore "div by zero":

*float leftValue = getEvaluation();
       divOpExp.prendiDestra().accept(this);
       float rightValue = getEvaluation();
       try {
              value = leftValue/rightValue;  // possibile divisione
per zero !!
           }
       catch (ArithmeticException exc){
           System.out.println("---------Divisione per zero------------");
           return false; }
       return true;*

nel risultato in* value* mette Infinity, il quale a sua volta non
riesco neanche a confrontarlo!
Alla fine mi torna un true!

hai provato a cercare su google java division by zero?

http://java.sun.com/developer/TechTips/1998/tt0722.html

In the Java programming language, integral division by zero results in an
ArithmeticException. But for floating-point, no exception is thrown (in C++
the result of division by zero is undefined). The result of 1.0 / 0.0 is
positive infinity, indicated by the constant Double.POSITIVE_INFINITY (which,
in fact, is defined by performing this division).

This example illustrates an important point, which is that Java language
floating-point arithmetic operates according to a well-defined standard, known
as IEEE 754.

filippo
Grazie! Avevo notato questa cosa, avevo cercato con google, ma non avevo cercato bene: non avevo il percorso della costante nelle API Java


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